Simplifying $4^{- 2} + 4^{- 1} + 4^{0} + 4^{2}$ gives

True

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False

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$\frac{257}{16}$

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$\frac{271}{18}$

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Solution

The correct option is A
True

$4^{- 2} + 4^{- 1} + 4^{0} + 4^{2}$
$= \frac{1}{16} + \frac{1}{4} + 1 + 16$
$= \frac{1 + 4 + 16 + 256}{16}$
$= \frac{277}{16}$

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4^{- 2} + 4^{- 1} + 4^{0} + 4^{2}

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