Simplifying : $4^{- 2} + 4^{- 1} + 4^{0} + 4^{2}$ gives

True

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False

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$\frac{257}{16}$

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$\frac{271}{18}$

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Solution

The correct option is A
True

$4^{- 2} + 4^{- 1} + 4^{0} + 4^{2} = \frac{1}{16} + \frac{1}{4} + 1 + 16$
$= \frac{1 + 4 + 16 + 256}{16} = \frac{277}{16}$

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Similar questions

4^{- 2} + 4^{- 1} + 4^{0} + 4^{2}

4^{- 2} + 4^{- 1} + 4^{0} + 4^{2}

Evaluate: $4^{- 2}$ + $4^{- 1}$ + $4^{0}$ + $4^{2}$

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