Sin-12a1-a2-cos-11-b21-b2-2tan-1x-

We have, #10; #10; sin^ 12a1+a^2+ cos #10;^ 1 1 b^21+b^2=2 tan^ 1x #10; #10; 2 tan^ 1a+2 tan^ 1b=2 tan #10;^ 1x #10; #10; ⇒tan^ 1a ...

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Circular Measurement of Angle

sin-12a1+a2+c...

Question

${sin}^{- 1} \frac{2 a}{1 + a^{2}} + {cos}^{- 1} \frac{1 - b^{2}}{1 + b^{2}} = 2 {tan}^{- 1} x$ .

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