Sin -1sin2 -3-cos -1cos7 -6-tan -1tan3 -4 is equal to-

Sin ^ 1(√(3)2)+cos ^ 1( √(3)2)+tan ^ 1( 1) =π3+5 π6 π4 =4 π+10 π 3 π12=11 π12 ...

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Trigonometric Functions

sin -1sin2 π3...

Question

${sin}^{- 1} (sin \frac{2 π}{3}) + {cos}^{- 1} (cos \frac{7 π}{6}) + {tan}^{- 1} (tan \frac{3 π}{4})$ is equal to:

\frac{17 π}{12}

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\frac{11 π}{12}

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\frac{31 π}{12}

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- \frac{3 π}{4}

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Solution

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Similar questions

{cos}^{- 1} (cos \frac{7 π}{6})

\frac{4 \sin θ - \cos θ}{4 \sin θ + \cos θ}

{sin}^{- 1} (sin \frac{2 π}{3}) + {cos}^{- 1} (cos \frac{7 π}{6}) + {tan}^{- 1} (tan \frac{3 π}{4})

{sin}^{- 1} (\frac{2 π}{4})

{cos}^{- 1} (cos \frac{7 π}{6})

{tan}^{- 1} (tan \frac{2 π}{3})

cos ({cos}^{- 1} (\frac{\sqrt{3}}{2}) + \frac{π}{6})

s i n^{- 1} (s i n \frac{2 π}{3}) = \frac{2 π}{3}

t a n^{- 1} (t a n \frac{2 π}{3}) = \frac{- π}{3}

c o s^{- 1} (c o s \frac{2 π}{3}) = \frac{2 π}{3}

s e c^{- 1} (s e c \frac{5 π}{4}) = \frac{3 π}{4}

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