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Question

sin1(sin2π3)+cos1(cos7π6)+tan1(tan3π4) is equal to:

A
17π12
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B
11π12
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C
31π12
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D
3π4
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Solution

The correct option is B 11π12
sin1(32)+cos1(32)+tan1(1)
=π3+5π6π4
=4π+10π3π12=11π12

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