Question

$Si{n}^{-1}x+Si{n}^{-1}y=\frac{\pi }{2}$ then $\frac{dy}{dx}=$

• A. $-\frac{x}{y}$
  
• B. $-\frac{y}{x}$
  
• C. $\frac{x}{y}$
  
• D. $\frac{y}{x}$

Answer 1

The correct option is A $-\frac{x}{y}$


If $Si{n}^{-1}x+Si{n}^{-1}y=\frac{\pi }{2},thenx=\sqrt{1-y^2}$
or $x^2+y^2=1\Rightarrow 2x+wy\frac{dy}{dx}=0$
$\Rightarrow \frac{dy}{dx}=\frac{-x}{y}$