Question

${\sin }^{-1}x$ ${\tan }^{-1}x$
when $x\in (0,1]$

• A. $\ge$
• B. $\le$
• C. >
• D. <

Answer 1

The correct option is C >


from above graph we can see that ${\sin }^{-1}x>{\tan }^{-1}x$ in the interval $(0,\frac{\pi }{2}]$