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Byju's Answer
Standard X
Mathematics
Trigonometric Identities
sin 2 A cos 2...
Question
(
s
i
n
2
A
c
o
s
2
B
−
c
o
s
2
A
s
i
n
2
B
)
=
A
s
i
n
2
A
+
s
i
n
2
B
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B
s
i
n
2
A
−
s
i
n
2
B
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C
c
o
s
2
A
−
s
i
n
2
B
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D
c
o
s
2
A
+
s
i
n
2
B
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Solution
The correct option is
B
s
i
n
2
A
−
s
i
n
2
B
=
(
s
i
n
2
A
c
o
s
2
B
−
c
o
s
2
A
s
i
n
2
B
)
=
s
i
n
2
A
(
1
−
s
i
n
2
B
)
−
(
1
−
s
i
n
2
A
)
s
i
n
2
B
=
1.
s
i
n
2
A
−
s
i
n
2
A
.
s
i
n
2
B
−
1.
s
i
n
2
B
+
s
i
n
2
A
.
s
i
n
2
B
=
s
i
n
2
A
−
s
i
n
2
B
Suggest Corrections
0
Similar questions
Q.
Prove that (sin
2
A cos
2
B - cos
2
A sin
2
B)= (sin
2
A-sin
2
B)
Q.
The given relation
s
i
n
2
A
c
o
s
2
B
+
c
o
s
2
A
s
i
n
2
B
+
c
o
s
2
A
c
o
s
2
B
+
s
i
n
2
A
s
i
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2
B
=
2
is
Q.
Prove that
(
i
)
(
s
i
n
2
A
c
o
s
2
B
−
c
o
s
2
A
s
i
n
2
B
)
=
(
s
i
n
2
A
−
s
i
n
2
B
)
(
i
i
)
(
t
a
n
2
A
s
e
c
2
B
−
s
e
c
2
A
t
a
n
2
B
)
=
(
t
a
n
2
A
−
t
a
n
2
B
)
[2 MARKS]
Q.
The value of
sin
2
A
cos
2
B
+
cos
2
A
cos
2
B
+
sin
2
A
sin
2
B
is...
Q.
Prove the following trigonometric identities.
sin
2
A cos
2
B − cos
2
A sin
2
B = sin
2
A − sin
2
B