Sin 2- is equal to 2tan-1-tan2 -

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Sin(A+B)Sin(A-B)

sin 2θ is equ...

Question

$sin 2 θ$ is equal to $\frac{2 tan θ}{1 - {tan}^{2} θ}$

True

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False

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Solution

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Similar questions

If $θ = 30^{o}$ ,verify that:

(i) $t a n 2 θ = \frac{2 t a n θ}{1 - t a n^{2} θ}$

(ii) $s i n 2 θ = \frac{2 t a n θ}{1 + t a n^{2} θ}$

(iii) $c o s 2 θ = \frac{1 - t a n^{2} θ}{1 + t a n^{2} θ}$

(iv) $c o s 3 θ = 4 c o s^{3} θ - 3 c o s θ$

\frac{{cos}^{2} θ + {tan}^{2} θ - 1}{{sin}^{2} θ} = {tan}^{2} θ

θ = 45

\frac{2 tan θ}{1 + {tan}^{2} θ}

{sin}^{2} θ + \frac{1}{1 + {tan}^{2} θ} =

\frac{c o s^{2} θ + t a n^{2} θ - 1}{s i n^{2} θ} = t a n^{2} θ

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