${sin}^{2} θ + {sin}^{2} (90^{o} - θ) = . . . . . . . . . . .$

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Solution

The value of ${sin}^{2} θ + {sin}^{2} (90^{o} - θ)$ is
$= {sin}^{2} θ + {cos}^{2} θ$
$= 1$

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