Question

$sin{20}^{\circ }sin{40}^{\circ }sin{60}^{\circ }sin{80}^{\circ }$=

• A. -3/16
• B. 5/16
• C. 3/16
• D. -5/16

Answer 1

The correct option is C

3/16

$sin{20}^{o}sin{40}^{\circ }sin{60}^{\circ }sin{80}^{\circ }$
=$\frac{1}{2}sin{20}^{\circ }sin{60}^{\circ }\left(2sin{40}^{\circ }sin{80}^{\circ }\right)$
=$\frac{1}{2}sin{20}^{\circ }sin{60}^{\circ }(cos{40}^{\circ }-cos{120}^{\circ })$
=$\frac{1}{2}.\frac{\sqrt{3}}{2}sin{20}^{\circ }(1-2si{n}^2{20}^{\circ }+\frac{1}{2})$
=$\frac{\sqrt{3}}{4}sin{20}^{\circ }(\frac{3}{2}-2si{n}^2{20}^{\circ })$
=$\frac{\sqrt{3}}{8}(3sin{20}^{\circ }-4si{n}^3{20}^{\circ })$
=$\frac{\sqrt{3}}{8}sin{60}^{\circ }=\frac{\sqrt{3}}{8}.\frac{\sqrt{3}}{2}=\frac{3}{16}$