Sin 25-sin 50-sin 90- 40- 65-

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Byju's Answer

Standard X

Mathematics

Trigonometric Ratios of Complementary Angles

sin 25∘sin 50...

Question

sin 25° sin 50° sin 90° sec 40° sec 65° = ___.

-1

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Solution

The correct option is C
1

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Similar questions

Show that :
(i) $\sin 50 ° \cos 85 ° = \frac{1 - \sqrt{2} \sin 35 °}{2 \sqrt{2}}$

(ii) $\sin 25 ° \cos 115 ° = \frac{1}{2} (\sin 140 ° - 1)$

Show that:
(i) $s i n 50^{\circ} c o s 85^{\circ} = \frac{1 - \sqrt{2} s i n 35^{\circ}}{2 \sqrt{2}}$
(ii) $s i n 25^{\circ} c o s 115^{\circ} = \frac{1}{2} (s i n 140^{\circ} - 1)$

Q. Evaluate :

\frac{sin 25^{\circ}}{sec 65^{\circ}} + \frac{cos 25^{\circ}}{c o s e c 65^{\circ}}

Q. Solve:

∣ ∣ ∣ \frac{sin 50}{cos 40} + \frac{csc 40}{sec 50} - 4 cos 50 x csc 40 ∣ ∣ ∣

Q. In fig. 8.19 write tan 50

°

, sec 40

°

, sin 50

°

, cos 60

°

, cot 60

°

, cosec 40

°

, cos 30

°

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sin 25° sin 50° sin 90° sec 40° sec 65° = ___.

The correct option is C 1

The correct option is C
1