Sin 2 n-1 A sin A-sin 2n-1 A-sin 2 n A - Prove this

Sin2(n+1)A sin2nA = sin(2n+1)A.sinA we have formula sin2a sin2b =sin(a b)sin(a+b) therefore sin2(n+1)A sin2nA=sin[(n+1)A+nA].sin[(n+1) ...

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Composite Function

sin 2 n+1 A s...

Question

sin(2n+1)AsinA=sin²(n+1)A-sin²nA . Prove this .

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