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Question

sin2x(1+tanx)=3sinx(cosxsinx)+3

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Solution

sin2x(1+tanx)=3sinxcosx+3cos2x
Divide throughput by cos2x(cosx0) and put tanx=t
t2(1+t)=3(t+1)
or t+1=0 or t2=3
tanx=1 or ±3
x=nππ4 or nπ±π3.

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