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Byju's Answer
Standard XII
Mathematics
Monotonically Increasing Functions
sin2x1+tan x=...
Question
sin
2
x
(
1
+
tan
x
)
=
3
sin
x
(
cos
x
−
sin
x
)
+
3
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Solution
sin
2
x
(
1
+
tan
x
)
=
3
sin
x
cos
x
+
3
cos
2
x
Divide throughput by
cos
2
x
(
cos
x
≠
0
)
and put
tan
x
=
t
t
2
(
1
+
t
)
=
3
(
t
+
1
)
or
t
+
1
=
0
or
t
2
=
3
∴
tan
x
=
−
1
or
±
√
3
∴
x
=
n
π
−
π
4
or
n
π
±
π
3
.
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