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Question

sin 2xa2+b2 sin2 x

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Solution

Let I=sin 2xa2+b2 sin2xdxPutting a+b2 sin2x=tb2 2 sin x cos x dx=dtb2×sin 2x dx=dtI=1b2dtt =1b2ln t+C =1b2ln a2+b2 sin2x+C t= a+b2 sin2x

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