Question

$\sin {30}^{\circ }\cos {60}^{\circ }+\sin {60}^{\circ }\cos {30}^{\circ }$ is equal to

• A. $\frac{1}{2}$
• B. $\frac{\sqrt{3}}{2}$
• C. $1$
• D. $\frac{1}{4}$

Answer 1

The correct option is C $1$

Given: $\sin {30}^o\cos {60}^o+\sin {60}^o\cos {30}^o$

(Putting the values as per trigonometry table)

$=\frac{1}{2}\times \frac{1}{2}+\frac{\sqrt{3}}{2}\times \frac{\sqrt{3}}{2}$

$=\frac{1}{4}+\frac{3}{4}=\frac{4}{4}=1$