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Byju's Answer
Standard X
Mathematics
Range of Trigonometric Ratios from 0 to 90 Degrees
sin 3A= 1 and...
Question
sin
3
A
=
1
and
0
≤
A
≤
90
0
. If
cos
2
A
is
m
2
, then
m
is:
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Solution
Given:
s
i
n
3
A
=
1
s
i
n
3
A
=
s
i
n
90
3
A
=
90
A
=
30
Now,
c
o
s
2
A
=
c
o
s
60
=
1
2
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0
Similar questions
Q.
If
sin
3
A
=
1
and
0
≤
A
≤
90
0
, then find the value of
1
cos
2
A
−
tan
2
A
Q.
sin
3
A
=
1
and
0
≤
A
≤
90
0
.
If
sin
A
is
1
m
, then
m
is:
Q.
If $
sin
3
A
=
1
sin3A=1
a
n
d
0
≤
A
≤
90
∘
0≤A≤90∘
$, find :
−
(
tan
2
A
−
1
cos
2
A
)
Q.
Given:
s
i
n
3
A
=
1
, then
If
c
o
s
2
A
is
m
2
, m is
Q.
If
sin
A
+
cos
2
A
=
1
/
2
and
cos
A
+
sin
2
A
=
1
/
3
,
then find the value of
sin
3
A
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Standard X Mathematics
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