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Range of Trigonometric Ratios from 0 to 90 Degrees

sin 3A= 1 and...

Question

$sin 3 A = 1$ and $0 \leq A \leq 90^{0}$ . If $sin A$ is $\frac{1}{m}$ , then $m$ is:

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Solution

$s i n 3 A = 1$
$s i n 3 A = s i n 90$
$3 A = 90$
$A = 30^{\circ}$
Now, $s i n A = s i n 30 = \frac{1}{2}$

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