$(sin 3 A + sin A) sin A + (cos 3 A - cos A) cos A = ?$

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Solution

The correct option is B $0$
$(sin 3 A + sin A) S i n A + (cos 3 A - cos A) cos A$
$\Rightarrow 2 sin 2 A . cos A . sin A + 2 sin 2 A . sin (- A) . cos A [∵ sin - A = - sin A]$
$\Rightarrow 2 sin 2 A . cos A sin A - 2 sin 2 A . sin A . cos A = 0$

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