Question

$sin{50}^0$ - $sin{70}^0$ + $sin{10}^0$ =

[MNR 1979]

• A. 1
• B. 0
• C. 1/2
• D. 2

Answer 1

The correct option is B

0

$sin{50}^0$ - $sin{70}^0$ + $sin{10}^0$

= $-2cos{60}^0$ $sin{10}^0$ + $sin{10}^0$

= $sin{10}^0$ $(1-2cos{60}^0)$ = 0.