sin #160;57^∘ cos #160;33^∘ = sin (90 33)^∘ cos #160;33^∘ = cos #160;33^∘ cos #160;33^∘ = 0^o ...

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Complementary Trigonometric Ratios

sin 57∘ - cos...

Question

$sin 57^{\circ} - cos 33^{\circ}$

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Solution

$sin 57^{\circ} - cos 33^{\circ}$
= $sin (90 - 33)^{\circ} - cos 33^{\circ}$
= $cos 33^{\circ} - cos 33^{\circ}$
= $0^{o}$

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Similar questions

sin A = cos 33^{\circ}

A

sin 18^{\circ} \cdot cos 39^{\circ} + sin 6^{\circ} \cdot cos 15^{\circ} = - sin 24^{\circ} \cdot cos 33^{\circ}

sin 18^{\circ} cos 39^{\circ} + sin 6^{\circ} cos 15^{\circ} = sin 24^{\circ} cos 33^{\circ}

\frac{5 sin 17^{o}}{cos 73^{o}} + \frac{2 cos 33^{o}}{sin 57^{o}} - \frac{7 sin 80^{o}}{cos 10^{o}}

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