Question

$sin{60}^{\circ }=2sin{30}^{\circ }cos{30}^{\circ }$
If true then write 1 and if false then write 0.

Answer 1

To Prove: $\sin {60}^0=2\sin {30}^0\cos {30}^0$
L.H.S.: $sin{60}^{\circ }=\frac{\sqrt{3}}{2}$
R.H.S.: $2\sin {30}^{\circ }\cos {30}^{\circ }=2\times \frac{1}{2}\times \frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{2}$
Thus, $L.H.S.=R.H.S$