sin 60° cos 30° + cos 60° sin 30°

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Solution

On substituting the values of various T-ratios, we get:
sin 60^o cos 30^o + cos 60^o sin 30^o
$= (\frac{\sqrt{3}}{2} \times \frac{\sqrt{3}}{2} + \frac{1}{2} \times \frac{1}{2}) = (\frac{3}{4} + \frac{1}{4}) = \frac{4}{4} = 1$

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