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Question

sin(60° + A) cos(30° - B) + cos(60° + A) sin(30° - B) is equal to


A

cos(A – B)

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B

sin(A + B)

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C

cos(A + B)

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D

sin(A – B)

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Solution

The correct option is A

cos(A – B)


By using, sin(x + y) = sinx cosy + cosx siny

sin[ (60° + A) + (30° - B) ] = sin[90° + ( A - B)] = cos(A – B)


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