Question

Sin 65/cos 25 + cos32/sin58 - sin28 × sec 62 + cosec^​​2​30 = ?

Plz note they are degrees. Thank you

Answer 1

Formulas used
1.Sin A = Cos(90 - A) and vice versa
2.Cos A = 1/Sec A and vice versa
3.Cosec^2 30 = 2^2=4

⇒ sin 65/cos 25 + cos 32/sin 58 - sin28.sec62 + cosec^2 30


Formulas Used Below 1 and 2
⇒sin 65/ cos(90-65) + cos 32 / sin(90 - 32) - cos(90 - 28). (1/cos 62) + cosec^2 30
⇒sin 65/sin 65 + cos 32/cos 32 - cos 62/cos 62 + cosec^2 30
= 1 + 1 - 1 + 4 ------[Cosec^2 30 = 4]
=1 + 4 = 5
Hope u Understood

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