Question

$\sin {75}^0=$

• A. $\frac{2-\sqrt{3}}{2}$
• B. $\frac{\sqrt{3}+1}{2\sqrt{2}}$
• C. $\frac{\sqrt{3}-1}{-2\sqrt{2}}$
• D. $\frac{\sqrt{3}-1}{2\sqrt{2}}$

Answer 1

The correct option is B $\frac{\sqrt{3}+1}{2\sqrt{2}}$

$\sin {75}^{\circ }=\sin ({90}^{\circ }-{15}^{\circ })$
$=\cos {15}^{\circ }=\cos ({45}^{\circ }-{30}^{\circ })$
$=\frac{\sqrt{3}+1}{2\sqrt{2}}$