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Byju's Answer
Standard XII
Mathematics
AM,GM,HM Inequality
Sin A and Sin...
Question
Sin A and Sin B are the roots of the equation
c
x
2
−
c
(
a
+
b
)
x
+
a
b
=
0
. Then Sin C
=
A
0
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B
1
2
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C
1
√
2
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D
1
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Solution
The correct option is
D
1
sin
A
+
sin
B
=
a
+
b
c
....eq(i)
sin
A
a
=
sin
B
b
=
sin
C
c
=
k
sin
A
=
k
a
,
sin
B
=
k
b
,
sin
C
=
k
c
.....substitute the values of a,b,c in eq(i)
s
i
n
A
+
s
i
n
B
=
sin
A
k
+
sin
B
k
sin
c
k
sin
c
=
1
.
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Similar questions
Q.
If the roots of the equation
a
(
b
−
c
)
x
2
+
b
(
c
−
a
)
x
+
c
(
a
−
b
)
=
0
are equal, show that
2
b
=
1
a
+
1
c
Q.
Let
A
+
B
+
C
=
π
and
α
=
sin
3
(
B
+
C
)
⋅
sin
(
2
C
+
A
)
,
β
=
sin
3
(
A
+
C
)
⋅
sin
(
2
A
+
B
)
,
γ
=
sin
3
(
A
+
B
)
⋅
sin
(
2
B
+
C
)
are roots of the cubic equation
x
3
+
a
x
2
+
b
x
+
c
=
0
, then the value of
a
is
Q.
Let
A
≡
(
1
+
sin
α
,
cos
α
)
;
B
≡
(
1
−
cos
β
,
−
sin
β
)
. If
sin
α
,
sin
β
are the roots of quadratic equation
3
sin
θ
−
2
sin
2
θ
−
1
=
0
where
0
≤
θ
≤
π
2
and the distance
A
B
=
√
a
+
√
b
units
, then
a
+
b
=
Q.
Let
A
≡
(
1
+
sin
α
,
cos
α
)
;
B
≡
(
1
−
cos
β
,
−
sin
β
)
. If
α
,
β
are the roots of quadratic equation
3
sin
θ
−
2
sin
2
θ
−
1
=
0
where
0
≤
θ
≤
π
2
and the distance
A
B
=
√
a
+
√
b
units
, then
a
+
b
=
Q.
The two roots of the equation
a
(
b
−
c
)
x
2
+
b
(
c
−
a
)
x
+
c
(
a
−
b
)
=
0
are 1 and:
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