Sin B-C/2 is equal to b-c/a cos A/2

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(cos A + sin A)^{2} - (cos A - sin A)^{2}

(cos A + sin)^{2} - (cos A - sin A)^{2}

\frac{{sin}^{2} A - {sin}^{2} B}{sin A cos A - sin B cos B}

{sin}^{2} A + {sin}^{2} (A - B) + 2 sin A cos B sin (B - A)

sin A + cos A = \sqrt{2}

sin A - cos A

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