The correct option is A 2√(126)/65 sin ( 2 sin^ 1√(63/65)) Use the result 2sin^ 1x=sin^ 1(2x√(1 x^2)). sin ( sin^ 1 ( 2√(63/65)√(1 63/65) ) )=2√(63/65 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XI

Mathematics

Definition of Functions

sin2 sin -1√6...

Question

$s i n (2 s i n^{- 1} \sqrt{\frac{63}{65}}) =$

$\frac{2 \sqrt{126}}{65}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{4 \sqrt{63}}{65}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{8 \sqrt{63}}{65}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{\sqrt{65}}{63}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$\frac{2 \sqrt{126}}{65}$

$s i n (2 s i n^{- 1} \sqrt{\frac{63}{65}})$
Use the result $2 s i n^{- 1} x = s i n^{- 1} (2 x \sqrt{1 - x^{2}})$ .
$s i n (s i n^{- 1} (2 \sqrt{\frac{63}{65}} \sqrt{1 - \frac{63}{65}})) = 2 \sqrt{\frac{63}{65}} \sqrt{\frac{2}{65}} = \frac{2 \sqrt{126}}{65}$

Suggest Corrections

Similar questions

$s i n (2 s i n^{- 1} \sqrt{\frac{63}{65}}) =$

sin (2 {sin}^{- 1} \sqrt{\frac{63}{65}})

is equal to :

$6^{5} - 6^{3} = ?$

{sin}^{- 1} \frac{3}{5} - {cos}^{- 1} \frac{63}{65} = {tan}^{- 1} \frac{253}{204}

Q. If

sin x = \frac{63}{65}, cos x = \frac{- 16}{65}

, the value of

tan (x) =

Join BYJU'S Learning Program

sin(2sin−1√6365)=

The correct option is A 2√12665 sin(2sin−1√6365) Use the result 2sin−1x=sin−1(2x√1−x2). sin(sin−1(2√6365√1−6365))=2√6365√265=2√12665

$s i n (2 s i n^{- 1} \sqrt{\frac{63}{65}}) =$