Sin -4 - -cos -4tan - - if - - n- -4- n - I- If true enter 1 else 0-

For θ = nπ π4 cot θ = tan θ = 1 ∴ sin [π4cot θ #160; #160; ] = 1 √(2), #160; #160; cos [π4tan θ #160; ]= 1 √(2) ...

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Standard X

Mathematics

Standard Values of Trigonometric Ratios

sin [π/4 θ ]=...

Question

$sin [\frac{π}{4} cot θ] = cos [\frac{π}{4} tan θ]$ , if $θ = n π - \frac{π}{4}, n \in I$ . If true enter 1 else 0.

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Solution

For $θ = n π - \frac{π}{4}$
$c o t θ = t a n θ = - 1$
$∴ s i n [\frac{π}{4} c o t θ] = - \frac{1}{\sqrt{2}}, c o s [\frac{π}{4} t a n θ] = \frac{1}{\sqrt{2}}$

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Similar questions

Which of the following statements are correct?

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Solve the equation: $\sqrt{(\frac{1}{16} + c o s^{4} x - \frac{1}{2} c o s^{2} x)} + \sqrt{(\frac{9}{16} + c o s^{4} x - \frac{3}{2} c o s^{2} x)} = \frac{1}{2}$

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sin[π4cotθ]=cos[π4tanθ], if θ=nπ−π4,n∈I. If true enter 1 else 0.

For θ=nπ−π4cotθ=tanθ=−1∴sin[π4cotθ]=−1√2,cos[π4tanθ]=1√2

$sin [\frac{π}{4} cot θ] = cos [\frac{π}{4} tan θ]$ , if $θ = n π - \frac{π}{4}, n \in I$ . If true enter 1 else 0.

For $θ = n π - \frac{π}{4}$
$c o t θ = t a n θ = - 1$
$∴ s i n [\frac{π}{4} c o t θ] = - \frac{1}{\sqrt{2}}, c o s [\frac{π}{4} t a n θ] = \frac{1}{\sqrt{2}}$