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Byju's Answer
Standard IX
Mathematics
Trigonometric Ratios of Complementary Angles
sinsin -1 1 2...
Question
sin
{
sin
−
1
1
2
+
cos
−
1
1
2
}
=
A
0
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B
−
1
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C
2
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D
1
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Solution
The correct option is
D
1
We know,
sin
−
1
θ
+
cos
−
1
θ
=
π
2
∴
sin
{
sin
−
1
1
2
+
cos
−
1
1
2
}
=
sin
(
π
2
)
=
1
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0
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Q.
Solve:
sin
{
sin
−
1
(
1
−
√
3
2
√
2
)
+
cos
−
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(
√
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+
1
2
√
2
)
}
Q.
If
sin
(
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1
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x
)
=
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then
x
is equal to
Q.
If
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sin
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+
cos
−
1
x
)
=
1
, then
x
=
Q.
sin
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-
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+
cos
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Q.
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i
n
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s
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n
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, then x is equal to