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Question

sin p = sin q .So, p=?


A

2nπ + (-1)nq, where n ЄZ

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B

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C

nπ + (-1)nq, where n ЄZ

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D

(2n + 3)π + (-1)nq, where n ЄZ

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Solution

The correct option is C

nπ + (-1)nq, where n ЄZ


Formula says, sin x= sin y, then

x = nπ + (-1)nγ, where n ЄZ .Hence the answer.


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