Sin- -cos- -1 find - where -2- -2

sinθ +cosθ =1 sinθ√(2)+cosθ√(2)= 1√(2) sinθcosπ 4+cosθsinπ 4=sinπ 4 sin(θ +π 4 )=sinπ 4 θ =0 ...

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Principal Solution of Trigonometric Equation

sinθ +cosθ =1...

Question

$sin θ + cos θ = 1$ find $θ$ where $θ ϵ (\frac{- π}{2}, \frac{π}{2})$

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m

\sqrt{\frac{1 - sin θ}{1 + sin θ}} + \sqrt{\frac{1 + sin θ}{1 - sin θ}} = \frac{- m}{cos θ}, \frac{π}{2} < θ < π

cos θ - sin θ = \frac{1}{5}

0 < θ < \frac{π}{2}

θ ϵ [\frac{- π}{2}, \frac{3 π}{2}]

c o s θ > s i n θ

cos (θ - α) = a, sin (θ - β) = b

(θ - α, θ - β) \in (0, \frac{π}{2})

lim θ \to \frac{π}{4} \frac{\sqrt{2 - cos θ - sin θ}}{{(4 θ - π)}^{2}}

\frac{1}{b \sqrt{2}}

b

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