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Question

sinθ=cosθ
find 2tanθ+cos2θ

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Solution

Consider the given equation and expression,

sinθ=cosθ ……(1) and 2tanθ+cos2θ …..(2)

Now, from equation (2),


2.tanθ+cos2θ

2.sinθcosθ+cos2θ


From equation (1),

2.cosθcosθ+cos2θ

2+cos2θ

cos2θ+2


Hence, this is the answer.

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