Sin -cos - -sin -cos - -

The correct option is D 0We know that, sin ( θ)= sinθ cos( θ)=cosθ ( θ)=θ and sin(π θ)=sinθ cos(π θ)= cosθ (π θ)= θ Putting all these values in the given equat ...

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Byju's Answer

Standard XI

Mathematics

Trigonometric Ratios of Allied Angles

sin -θ+cos -θ...

Question

$sin (- θ) + cos (- θ) + sec (- θ) + sin (π - θ) + cos (π - θ) + sec (π - θ) =$

2 sin θ

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2 cos θ

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2 sec θ

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Solution

The correct option is D $0$
We know that,
$sin (- θ) = - sin θ$
$cos (- θ) = cos θ$
$sec (- θ) = sec θ$
and
$sin (π - θ) = sin θ$
$cos (π - θ) = - cos θ$
$sec (π - θ) = - sec θ$

Putting all these values in the given equation, we get,
$- sin θ + cos θ + sec θ + sin θ - cos θ - sec θ = 0$

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