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Question

sinx=6sin30o8cos60o+2tan45o2(sin230o+cos260o), then x= how much?

A
30o
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B
45o
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C
60o
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D
90o
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Solution

The correct option is C 90o
sinx=6sin30o8cos60o+2tan45o2(sin230o+sin260o)
sinx=6×128×512+22((12)2+(12)2)=3.4+22(12)=11
sinx=1
x=90o.
Hence, option D is correct.

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