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Byju's Answer
Standard X
Mathematics
Relation between Trigonometric Ratios
sin 222∘+sin ...
Question
(
sin
2
22
°
+
sin
2
68
°
)
(
cos
2
22
°
+
cos
2
68
°
)
+
sin
2
63
°
+
cos
63
°
sin
27
=
?
(a) 0
(b) 1
(c) 2
(d) 3
Open in App
Solution
(c) 2
We have:
[
sin
2
22
0
+
sin
2
68
0
cos
2
22
0
+
cos
2
68
+
sin
2
63
0
+
cos
63
0
sin
27
0
]
=
[
sin
2
22
0
+
sin
2
(
90
0
−
22
0
)
cos
2
(
90
0
−
68
0
)
+
cos
2
68
0
+
sin
2
63
0
+
cos
63
0
{
sin
(
90
0
−
63
0
)
}
]
=
[
sin
2
22
0
+
cos
2
22
0
sin
2
68
0
+
cos
2
68
0
+
sin
2
63
0
+
cos
63
0
cos
63
0
]
[
∵
sin
(
90
0
−
θ
)
=
cos
θ
and
cos
(
90
0
−
θ
)
=
sin
θ
]
=
[
1
1
+
sin
2
63
0
+
cos
2
63
0
]
[
∵
sin
2
θ
+
cos
2
θ
=
1
]
=
1
+
1
=
2
Suggest Corrections
0
Similar questions
Q.
sin
2
22
°
+
sin
2
68
°
cos
2
22
°
+
cos
2
68
°
+
sin
2
63
°
+
cos
63
°
sin
27
°
Q.
The value of
(
(
s
i
n
2
22
∘
+
s
i
n
2
68
∘
c
o
s
2
22
∘
+
c
o
s
2
68
∘
)
+
s
i
n
2
63
∘
+
c
o
s
63
∘
s
i
n
27
∘
)
Q.
The value of the expression
sin
2
22
°
+
sin
2
68
°
cos
2
22
°
+
cos
2
68
°
+
sin
2
63
°
+
cos
63
°
sin
27
°
is ________.
Q.
{
(
s
i
n
2
22
o
+
s
i
n
2
68
o
)
(
c
o
s
2
22
o
+
c
o
s
2
68
o
)
+
s
i
n
2
63
o
+
c
o
s
63
o
s
i
n
27
o
}
= ?
(a) 0 (b) 1 (c) 2 (d) 3
Q.
Question 11
The value of the expression
(
s
i
n
2
22
∘
+
s
i
n
2
68
∘
c
o
s
2
22
∘
+
c
o
s
2
68
∘
+
s
i
n
2
63
∘
+
c
o
s
63
∘
27
∘
)
is
(A) 3
(B) 2
(C) 1
(D) 0
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