sin2θ + cos2θ = 1.

Therefore is ROOT of sin2theta + ROOT of cos2theta must be equal to ROOT of one ?

Basically is sin ROOT theta +cos ROOT theta = 1

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Solution

Basically, sin²ϴ +cos²ϴ =1
so,

√(sin²ϴ +cos²ϴ)=√1 = 1
so true

sin ROOT theta +cos ROOT theta is not equal to 1.

(sin√ϴ+cos√ϴ is not equal to one. )

Thank you :)

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sin2θ + cos2θ = 1. Therefore is ROOT of sin2theta + ROOT of cos2theta must be equal to ROOT of one ? Basically is sin ROOT theta +cos ROOT theta = 1

Basically, sin²ϴ +cos²ϴ =1 so, √(sin²ϴ +cos²ϴ)=√1 = 1 so true sin ROOT theta +cos ROOT theta is not equal to 1. ​​ (sin√ϴ+cos√ϴ is not equal to one. ) Thank you :) ​​​​​ ​​​

sin2θ + cos2θ = 1.

Therefore is ROOT of sin2theta + ROOT of cos2theta must be equal to ROOT of one ?

Basically is sin ROOT theta +cos ROOT theta = 1

Basically, sin²ϴ +cos²ϴ =1
so,

√(sin²ϴ +cos²ϴ)=√1 = 1
so true

sin ROOT theta +cos ROOT theta is not equal to 1.

(sin√ϴ+cos√ϴ is not equal to one. )

Thank you :)