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Byju's Answer
Standard XII
Mathematics
Differentiation of a Function
∫sin 32 x+1 d...
Question
∫
sin
3
2
x
+
1
d
x
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Solution
∫
sin
3
2
x
+
1
d
x
=
1
4
∫
3
sin
2
x
+
1
-
sin
3
2
x
+
1
d
x
∴
sin
3
θ
=
3
sin
θ
-
4
sin
3
θ
⇒
sin
3
θ
=
1
4
3
sin
θ
-
sin
3
θ
=
3
4
∫
sin
2
x
+
1
d
x
-
1
4
∫
sin
6
x
+
3
d
x
=
3
4
-
cos
2
x
+
1
2
-
1
4
-
cos
6
x
+
3
6
+
C
=
-
3
8
cos
2
x
+
1
+
1
24
cos
6
x
+
3
+
C
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