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Question

sin3 xcos x dx

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Solution

sin3 xcos xdx=sin2x·sin xcos x dx=1-cos2x sin xcos xdxLet cos x=t-sin x=dtdxsin x dx=-dtNow,1-cos2xsin xcos xdx=-1-t2tdt=t2-1tdt=t32-t-12dt=t32+132+1-t-12+1-12+1+C=25t52-2t+C=25 cos52x -2 cos x+C

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