Sin48.sec42+cos48.cosec42= ........
Prove that:
(i) tan 20o tan 35o tan 45o tan 55o tan 70o=1
(ii) sin 48o sec42o+cos 48o cosec 42o=2
(iii) sin 70ocos 20o+cosec 20osec 70o−2 cos 70o cosec 20o=0
(iv) cos 80osin 10o+cos 59o cosec 31o=2
Evaluate : cos48∘−sin42∘___