Sin5x-Sinx expressed as a product is
2cos3xsin2x
2cos2xsin3x
2sin3xcos2x
2sin2xcos3x
We know that sinA-sinB = 2cos((A+B)/2)sin((A-B)/2)
Using this and substituting, A=5x and B= x we get
Sin5x-Sinx=2 cos3xsin2x
Prove that sinx+sin7x+sin3x+sin5x=4cosxcos2xsin4x
Or
Solve √3cosx−sinx=1