Single Correct Answer TypeA ball is projected from a point A with some velocity at an angle 30- with the horizontal as shown in Fig- Consider a target at point B- The ball will hit the target if it is thrown with a velocity v0 equal to-

The correct option is D None of theseGiven: #160;Height = 0.5m, #160; g = 10 ms^2 Range = √(()32)m We know Range = #160; R=u^2sinθg √( ...

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Standard XII

Physics

Maximum Height

Single Correc...

Question

Single Correct Answer Type
A ball is projected from a point $A$ with some velocity at an angle $30^{\circ}$ with the horizontal as shown in Fig. Consider a target at point $B$ . The ball will hit the target if it is thrown with a velocity $v_{0}$ equal to:

5 m s^{- 1}

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6 m s^{- 1}

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7 m s^{- 1}

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None of these

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Solution

The correct option is D None of these
Given:-
Height = 0.5m, g = 10 $\frac{m}{s^{2}}$
Range = $\sqrt{(} \frac{3}{2}) m$
We know Range = $R = \frac{u^{2} s i n θ}{g}$
$\sqrt{(} \frac{3}{2}) = \frac{u^{2} s i n (60^{0})}{10}$
$u = 3.76 m s^{-} 1$

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Single Correct Answer TypeA ball is projected from a point A with some velocity at an angle 30∘ with the horizontal as shown in Fig. Consider a target at point B. The ball will hit the target if it is thrown with a velocity v0 equal to:

The correct option is D None of theseGiven:- Height = 0.5m, g = 10ms2Range = √(32)mWe know Range = R=u2sinθg√(32)=u2sin(600)10u=3.76ms−1

Single Correct Answer Type
A ball is projected from a point $A$ with some velocity at an angle $30^{\circ}$ with the horizontal as shown in Fig. Consider a target at point $B$ . The ball will hit the target if it is thrown with a velocity $v_{0}$ equal to:

The correct option is D None of these
Given:-
Height = 0.5m, g = 10 $\frac{m}{s^{2}}$
Range = $\sqrt{(} \frac{3}{2}) m$
We know Range = $R = \frac{u^{2} s i n θ}{g}$
$\sqrt{(} \frac{3}{2}) = \frac{u^{2} s i n (60^{0})}{10}$
$u = 3.76 m s^{-} 1$