Single Correct Answer TypeA ball is projected from a point A with some velocity at an angle 30- with the horizontal as shown in Fig- Consider a target at point B- The ball will hit the target if it is thrown with a velocity v0 equal to-

The correct option is D None of theseGiven: #160;Height = 0.5m, #160; g = 10 ms^2 Range = √(()32)m We know Range = #160; R=u^2sinθg √( ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Maximum Height

Single Correc...

Question

Single Correct Answer Type
A ball is projected from a point $A$ with some velocity at an angle $30^{\circ}$ with the horizontal as shown in Fig. Consider a target at point $B$ . The ball will hit the target if it is thrown with a velocity $v_{0}$ equal to:

5 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D None of these
Given:-
Height = 0.5m, g = 10 $\frac{m}{s^{2}}$
Range = $\sqrt{(} \frac{3}{2}) m$
We know Range = $R = \frac{u^{2} s i n θ}{g}$
$\sqrt{(} \frac{3}{2}) = \frac{u^{2} s i n (60^{0})}{10}$
$u = 3.76 m s^{-} 1$

Suggest Corrections

Similar questions

A ball is projected from a point A with some velocity at an angle $30^{\circ}$ with horizontal as shown in figure. Consider a target at point B. The ball will hit the target. It is thrown with velocity $v_{0}$ equal to

Q. Two stones

A

and

B

are projected from the same point.

B

is thrown

1

second after

A

is thrown.

A

is projected with a velocity of

60 m / s

at an angle

30^{\circ}

with the horizontal and

B

is projected with velocity

u

at an angle of

45^{\circ}

with the horizontal. Find

u

if both stones hit the ground at the same time. (Take

g = 10 m / s

)

Q. Single Correct Answer Type
A particle is projected at angle

α

to horizontal from foot of an inclined plane of angle

30^{\circ}

with a particular velocity. If particle strikes the plane normally then

α

is equal to -

Q. Single Correct Answer Type
A particle is projected from the ground with an initial speed of 'v' at angle

θ

with horizontal. the average velocity of the particle between its point of projection and height point of trajectory is

Q. Single Correct Answer Type
A projectile is thrown in upward direction making an angle of

60^{o}

with the horizontal direction with a velocity of

150 m s^{- 1}

. Then, the time after which its inclination with horizontal is

45^{o}

, is :

Join BYJU'S Learning Program

Single Correct Answer TypeA ball is projected from a point A with some velocity at an angle 30∘ with the horizontal as shown in Fig. Consider a target at point B. The ball will hit the target if it is thrown with a velocity v0 equal to:

The correct option is D None of theseGiven:- Height = 0.5m, g = 10ms2Range = √(32)mWe know Range = R=u2sinθg√(32)=u2sin(600)10u=3.76ms−1

Single Correct Answer Type
A ball is projected from a point $A$ with some velocity at an angle $30^{\circ}$ with the horizontal as shown in Fig. Consider a target at point $B$ . The ball will hit the target if it is thrown with a velocity $v_{0}$ equal to:

The correct option is D None of these
Given:-
Height = 0.5m, g = 10 $\frac{m}{s^{2}}$
Range = $\sqrt{(} \frac{3}{2}) m$
We know Range = $R = \frac{u^{2} s i n θ}{g}$
$\sqrt{(} \frac{3}{2}) = \frac{u^{2} s i n (60^{0})}{10}$
$u = 3.76 m s^{-} 1$