Question

Single Correct Answer Type
Horizontal range and maximum height of a projectile are $R$ and $H$. If a constant horizontal acceleration $a=g/4$ is given to projectile due to air then what will be the horizontal range and maximum height of projectile?

• A. $(R+H),\frac{H}{2}$
• B. $(R+\frac{H}{2}),2H$
• C. $(R+2H),H$
• D. $(R+H),H$

Answer 1

The correct option is D $(R+H),H$

As the acceleration is in horizontal direction it wont affect the height

$S=ut+0.5a{t}^2$

$R_1=u_{x}t+0.5\times 0.25g\times t^2$

time taken is $t=\frac{2u_y}{g}$

$R_1=\frac{2u_x{u}_y}{g}+0.5\times 0.25g\times \left(\frac{4u_y^2}{g^2}\right)$

$R_1=\frac{2u^{2}sin\theta cos\theta }{g}+\frac{u^{2}si{n}^2\theta }{2g}$

$R_1=R+H$