Sinusoidal carrier voltage of frequency $1.5 M H z$ and amplitude $50 V$ is amplitude modulated by sinusoidal voltage of frequency $10 k H z$ producing 50% modulation. The lower and upper side-band frequencies in $k H z$ are

1490, 1510

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1510, 1490

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\frac{1}{1490}, \frac{1}{1510}

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\frac{1}{1510}, \frac{1}{1490}

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Solution

The correct option is A $1490, 1510$
Here, $f_{c}$ = $1.5 M H z$ = $1500 k H z$ , $f_{m}$ = $10 k H z$
Low side band frequency=
$f_{c} - f_{m}$ = $1500 k H z - 10 k H z$
= $1490 k H z$
Upper side band frequency=
$f_{c} + f_{m}$ = $1500 k H z + 10 k H z$
= $1510 k H z$

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Sinusoidal carrier voltage of frequency 1.5 MHz and amplitude 50 V is amplitude modulated by sinusoidal voltage of frequency 10 kHz producing 50% modulation. The lower and upper side-band frequencies in kHz are

The correct option is A 1490,1510Here, fc = 1.5 MHz = 1500 kHz, fm =10 kHz Low side band frequency= fc−fm = 1500 kHz−10 kHz = 1490 kHz Upper side band frequency= fc+fm = 1500 kHz+10 kHz = 1510 kHz

Sinusoidal carrier voltage of frequency $1.5 M H z$ and amplitude $50 V$ is amplitude modulated by sinusoidal voltage of frequency $10 k H z$ producing 50% modulation. The lower and upper side-band frequencies in $k H z$ are

The correct option is A $1490, 1510$
Here, $f_{c}$ = $1.5 M H z$ = $1500 k H z$ , $f_{m}$ = $10 k H z$
Low side band frequency=
$f_{c} - f_{m}$ = $1500 k H z - 10 k H z$
= $1490 k H z$
Upper side band frequency=
$f_{c} + f_{m}$ = $1500 k H z + 10 k H z$
= $1510 k H z$