Sinusoidal carrier voltage of frequency, 1.5 MHz and amplitude 50 V is amplitude modulated by sinusoidal voltage of frequency 10 kHz producing 50% modulation. The lower and upper side-band frequencies in kHz are

1490, 1510

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1510, 1490

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\frac{1}{1490}, \frac{1}{1510}

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\frac{1}{1510}, \frac{1}{1490}

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Solution

The correct option is D 1490, 1510
Here, $f_{c} = 1.5 M H z = 1500 k H z, f_{m} = 10 k H z$
$∴$ Low side band frequency $= f_{c} - f_{m} = 1500 k H z - 10 k H z = 1490 k H z$
Upper side band frequency $= f_{c} + f_{m} = 1500 k H z + 10 k H z = 1510 k H z$

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A carrier wave of frequency 1.5 MHz and amplitude 50 V is modulated by a sinusoidal wave of frequency 10 kHz producing 50% amplitude modulation. Calculate the amplitude of the AM wave and frequencies of the side bands produced.

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Sinusoidal carrier voltage of frequency, 1.5 MHz and amplitude 50 V is amplitude modulated by sinusoidal voltage of frequency 10 kHz producing 50% modulation. The lower and upper side-band frequencies in kHz are

The correct option is D 1490, 1510Here, fc=1.5 MHz=1500 kHz, fm=10 kHz∴ Low side band frequency =fc−fm=1500kHz−10kHz=1490 kHzUpper side band frequency =fc+fm=1500kHz+10kHz=1510 kHz

The correct option is D 1490, 1510
Here, $f_{c} = 1.5 M H z = 1500 k H z, f_{m} = 10 k H z$
$∴$ Low side band frequency $= f_{c} - f_{m} = 1500 k H z - 10 k H z = 1490 k H z$
Upper side band frequency $= f_{c} + f_{m} = 1500 k H z + 10 k H z = 1510 k H z$