Question

Six boys and six girls sit in a row alternatively in x ways and at a round table (again alternatively) in y ways. Then

• A. x = y
• B. x = 12 y
• C. y = 12x
• D. x = 2y

Answer 1

The correct option is B x = 12 y

$x=\left(2\right)(6!{)}^2,(y)=5!6!x=2.6!6!$ $\Rightarrow x=2\left(6\right)5!6!=12y$