Question

Six boys and six girls sit in a row randomly. The probability that six girls sit together is

Answer 1

The number of ways in which all the six girls sit together is $6!\times 7!$ (considering all $6$ girls as one person). Therefore, the probability of all girls sitting together is $\frac{6!\times 7!}{12!}=\frac{720}{12\times 11\times 10\times 9\times 8}=\frac{1}{132}$