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Question
Six charges are kept at the vertices of a regular hexagon as shown in the figure. If the magnitude of a force applied by +Q on +q charges is F. then net electric force on the +Q is nF. Find the value of n.
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Solution
force between Q and q=F[F=KQq/r2]force between Q and -2q=−2KQq/r2=−2F =2F [along of]force betweenfo Q and +3q=3F[along of]net force along of=2F+3F=5Fforce between Q and -3q=−3KQq/r2=−3F =3F [along oe]force betweenfo Q and +q =F[along oe]net force along of=F+3F=4Fforce between Q and -4q =−4KQq/r2=−4F =4F [along od]force betweenfo Q and +q=F [along od]net force along of=F+4F=5Ftherefore:, resultant =vector(od)+vector(of) =5F{along oe} net resuitant force=5F+4F =9F[along oe] therefore n=9
force between Q and q=F[F=KQq/r2]
force between Q and -2q=−2KQq/r2=−2F
=2F [along of]
force betweenfo Q and +3q=3F[along of]
net force along of=2F+3F=5F
force between Q and -3q=−3KQq/r2=−3F
=3F [along oe]
force betweenfo Q and +q =F[along oe]
net force along of=F+3F=4F
force between Q and -4q =−4KQq/r2=−4F
=4F [along od]
force betweenfo Q and +q=F [along od]
net force along of=F+4F=5F
therefore:,
resultant =vector(od)+vector(of)
=5F{along oe}
net resuitant force=5F+4F
=9F[along oe]
therefore n=9
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