wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Six dice are stacked as shown in the figure. On each dice, the sum of number appearing on a face and on the face opposite to it is 7. What is the maximum possible sum of the numbers on the visible faces?
893272_925fb118044447ebbf59c7e8e81ce557.jpg

A
88
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
89
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
96
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
147
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 89
Sum of numbers on top dice = 20
Sum of number on left side dice in middle row = 13
Sum of number on right side dice in middle row = 13
Sum of numbers on left side dice in last row = 18
Sum of numbers on middle dice in last row = 7
Sum of numbers on right side dice in last row = 18
Total sum = 20+13+!3+18+7+18 =89
Hence, Option B is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Permutations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon