Six-digit odd numbers, greater than 6,00,000 that can be formed using the digits 5,6,7,8,9 and 0 if repetition of digits is allowed is
We have 6 digits, 5,6,7,8,9 and 0 and we have to form odd numbers greater than 6,00,000.
The unit's place can only be filled by 5,7 or 9 since we have to form odd numbers.
∴ The unit place can be filled in 3 ways.
The first place (lakh's position) can be occupied by the digits greater than or equal to 6. Therefore, the lakh's position can be filled in 4 ways.
Each of the remaining 4 places can be filled by any of the 6 digits in 64 ways.
Hence, the total number will be 4×6×6×6×6×3=15552